Simplifying Algebra: Grade 11 Maths Q

AI Thread Summary
The discussion revolves around simplifying the algebraic expression (4 - 1/x) / (4 + 1/x). Participants suggest clearing fractions by multiplying the numerator and denominator by x, which simplifies the expression to (4x - 1) / (4x + 1). They emphasize that simplifications should maintain the original equation's outcome, allowing verification by substituting values for x. While some participants provide hints and examples, they stress that the goal is to achieve a simpler form rather than a more complex one. The conversation highlights the importance of understanding fraction manipulation in algebra.
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I am in grade 11 mathematics...i got this as a Thinking & Problem Solving Q..can someone simplify this, step by step?


4 - 1/x
---------
4 + 1/x


THANKS!
 
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You need to show us some of your work or thoughts on the problem.

Here's a hint. Clear the fractions first.
 
ok..the way i thought was taking the negative reciprocal of the denominator..
making it (4-1/x)(4-1/x)
---------------
(4+1/x)(4-1/x)
=16-8 1/x+1/x^2
----------------
16-1/x^2

does that work?
I haven't been taught how the clear the fractions.
 
I haven't been taught how the clear the fractions.

Sure you have... Just think about it for a bit. What would you multiply top and bottom by?
 
jamie_23 said:
ok..the way i thought was taking the negative reciprocal of the denominator..
making it (4-1/x)(4-1/x)
---------------
(4+1/x)(4-1/x)
=16-8 1/x+1/x^2
----------------
16-1/x^2

does that work?
I haven't been taught how the clear the fractions.
Simplifying should never change the outcome of an equation. You can therefore check if your simplification is correct by letting x equal any number. The original and simplified equations will produce the same answer if the simplification is correct.

So, let x=2
Your first equation gives (4 - 1/2) / (4 + 1/2) = .77778
Your simplified equation gives (16 - 8/2 + 1/4) / (16 - 1/4) = .77778

So your simplification is correct however it is probably not a "simplification". It looks more complex. What Integral is saying is that you can get rid of a fraction by multiplying it (and all other parts of the equaion by the denomonator of the fraction. This is particularly usefull if you have the same problem in multiple parts fo the equation.

For example, (1 + 1/x) / (2 + 3/x) can be simplified by multiplying both the top and bottom lines by x (the denomonator of the fraction).

You then get (x + 1) / (2x + 3) - much simpler form than the original.
You can then multiply by the reciprical if you wish (gives you (-2x^2 + x + 3) / (-4x^2 + 9) ) but it is not as simple is it?

For the same reason as multiplying by the reciprical, multiplying both parts by the denomonator does not change the outcome of the equation because x/x = 1
 
jamie_23 said:
I am in grade 11 mathematics...i got this as a Thinking & Problem Solving Q..can someone simplify this, step by step?


4 - 1/x
---------
4 + 1/x


THANKS!

If I understand this correctly, (4-1/x)/(4+1/x)

I'm not going to asnwer the question for you. But let's look at something simplier. (1/2)/(1/8) to make things simple multiply the two together like this (1/2) * (8/1) = (8/2) or 4. Just flip the bottom term upside (take the reciprocal) & multiply. Hope that helps.
 
first, (4-1/x)/(4+1/x) common denominators maybe?
(4/x-1/x)/(4/x+1x)
than
[(4x-1)/x]/[(4x+1/x)]
Multiply by the recpricoal of the denominator now... Can you see?

You should see that some things will cancel.
 
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