Simplifying Expressions: Understanding 1/4k

Shackleford
Messages
1,649
Reaction score
2
I'm not seeing how you get 1/4k = (1/2)k(1/2)k(1/2)

I understand why you can factor out the (1/2). It's in each term of the sum.

http://i111.photobucket.com/albums/n149/camarolt4z28/Untitled-2.png?t=1297227186

I haven't really looked at this crap in four years.
 
Last edited by a moderator:
Physics news on Phys.org
That's not what they have. Although you can factor out the 1/2 because of the "+1" in the denominator of the expression.
 
Pengwuino said:
That's not what they have. Although you can factor out the 1/2 because of the "+1" in the denominator of the expression.

Yeah, I got the +1 part. I feel silly for not immediately following their steps.

(22)k?
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top