Simplifying Expressions with Boolean Algebra - Homework Help

AI Thread Summary
The discussion focuses on simplifying Boolean expressions using Boolean algebra. The user presented three expressions and their attempted simplifications, claiming to arrive at A, AC, and AB respectively. However, other participants pointed out errors in the simplifications, particularly questioning the replacement of A'B with 0 and the incorrect simplification of A' + A. They suggested using truth tables to verify the correctness of the results, highlighting that the simplifications did not yield equivalent expressions. The conversation emphasizes the importance of accuracy in Boolean algebra simplifications.
EEhokie13
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Homework Statement


Simplify the following expressions using Boolean Algebra.

a) A + AB (A or A and B)
b) A'BC + AC (A(not) and B and C or A and C)
c) A'B + ABC' + ABC (A(not) and B or A and B and C(not) or A and B and C)

Homework Equations


Some simple boolean algebra rules.
x+1=0
x*x=x
x*x'=0


The Attempt at a Solution



For a, I got the answer of A.
I did:
A(1 + B)
A(1)
= A

For b, I got the answer AC.

I did:
C(A'B + A)
C(0 + A)
= AC

For c, I got the answer AB.
I did:
B(A' + AC' + AC)
B(A' + (A.C') + (A.C))
B(A' + (0) + A)
B(A' + A)
B(A)
= AB

Are my calculations correct or am I completely wrong? Thank you for your help.
 
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EEhokie13 said:

Homework Statement


Simplify the following expressions using Boolean Algebra.

a) A + AB (A or A and B)
b) A'BC + AC (A(not) and B and C or A and C)
c) A'B + ABC' + ABC (A(not) and B or A and B and C(not) or A and B and C)

Homework Equations


Some simple boolean algebra rules.
x+1=0
x*x=x
x*x'=0


The Attempt at a Solution



For a, I got the answer of A.
I did:
A(1 + B)
A(1)
= A
Looks good.
For b, I got the answer AC.

I did:
C(A'B + A)
C(0 + A)
= AC
How did you replace A'B with 0?
For c, I got the answer AB.
I did:
B(A' + AC' + AC)
B(A' + (A.C') + (A.C))
B(A' + (0) + A)
B(A' + A)
B(A)
= AB
It's not clear what you did from the second to third line, and you simplified A'+A incorrectly.
Are my calculations correct or am I completely wrong? Thank you for your help.
When you have only a few variables, it's easy enough to verify that you simplified an expression correctly by writing out the truth table. For example, for A'BC+AC, you get
Code:
A B C   A'  A'BC   AC    A'BC+AC
T T T   F     F     T       T
T T F   F     F     F       F
T F T   F     F     T       T
T F F   F     F     F       F 
F T T   T     T     F       T
F T F   T     F     F       F
F F T   T     F     F       F
F F F   T     F     F       F
Comparing the columns for AC and A'BC+AC, you can see they're not equal, so you know something went wrong in the simplification.
 

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