Simplifying Inverse Laplace Transform of s/(s+4)^4

kiwifruit
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Homework Statement


the questions asks to determine inverse laplace transform of

s/(s+4)^4



Homework Equations





The Attempt at a Solution


this can supposedly be done just using laplace transform tables so I am guessing i need to simplify that to something that's workable but i don't know how.
the solution is
e^(-4t) (t^2/2 - (2/3) t^3)
anyone can help in directing me how to simplify that equation before i use tables to inverse?
 
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Welcome to PF, kiwifruit! :smile:

Which transforms can you find that are somewhat close to your question?
Or transforms that perhaps may be of help?
 
i would say
laplace of e^at = 1/(s-a)
or
laplace of cos(at) = s/(s^2 + a^2)
is similar to the question but i don't see how to simplify or factorize it to something workable
 
I find this formula frequently helpful:

\mathcal L^{-1}f(s+a) = e^{-at}\mathcal L^{-1}f(s)

If you rewrite the expression like this:
\frac{(s+4)-4}{(s+4)^3}
and break it apart, the answer should fall right out.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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