Simplifying Logarithmic Expressions to \log_x{y}

AI Thread Summary
The expression (\log_a{b})(\log_b{c})(\log_c{d}) can be simplified to \log_a{d} by converting all logarithms to a common base, such as base a. The transformation involves using the change of base formula, where \log_b{c} is expressed as \frac{\log_a{c}}{\log_a{b}} and \log_c{d} as \frac{\log_a{d}}{\log_a{c}}. This approach allows for the cancellation of terms, leading to the final simplified form. The discussion clarifies that "in terms of \log_x{y}" means expressing the logarithmic expression as a single logarithm. Overall, the simplification process emphasizes the importance of using a consistent logarithmic base.
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Homework Statement



Simplify (\log_a{b})(\log_b{c})(\log_c{d}) in terms of \log_x{y}

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The Attempt at a Solution



well , the furthest i can reach is

\frac{\log_xd}{\log_xa} , how do i express in terms of \log_x{y}
 
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Since there are no "x" or "y" in the problem I think you are misunderstanding.

"in term so log_x y" simply means "in terms of a single logarithm"

You could, for example, put everything in terms of a logarithm base a:
log_b c= \frac{log_a c}{log_a b}
and
log_c d= \frac{log_a d}{log_a c}
so
(log_a b)(log_b c)(log_c d)= (log_a b)\frac{log_a c}{log_a b}\frac{log_a d}{log_a c}= log_a d
 


HallsofIvy said:
Since there are no "x" or "y" in the problem I think you are misunderstanding.

"in term so log_x y" simply means "in terms of a single logarithm"

You could, for example, put everything in terms of a logarithm base a:
log_b c= \frac{log_a c}{log_a b}
and
log_c d= \frac{log_a d}{log_a c}
so
(log_a b)(log_b c)(log_c d)= (log_a b)\frac{log_a c}{log_a b}\frac{log_a d}{log_a c}= log_a d

thanks !
 
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