Single slit diffraction confusion

Click For Summary
SUMMARY

The discussion centers on the confusion surrounding single slit diffraction, particularly the method of calculating dark fringes. Participants clarify that while dividing the slit into four parts to analyze destructive interference at the second dark fringes is a common approach, it is an oversimplification. The accurate method involves treating each point of the slit as a separate wave source and integrating the path differences for precise calculations. This nuanced understanding is crucial for correctly interpreting diffraction patterns.

PREREQUISITES
  • Understanding of wave interference principles
  • Familiarity with single slit diffraction concepts
  • Knowledge of integral calculus for wave function analysis
  • Basic physics concepts related to light and optics
NEXT STEPS
  • Study the mathematical derivation of single slit diffraction patterns
  • Learn about wavefronts and Huygens' principle in optics
  • Explore numerical integration techniques for wave interference
  • Investigate the differences between single slit and double slit diffraction
USEFUL FOR

Students of physics, educators teaching optics, and anyone seeking a deeper understanding of wave behavior in diffraction scenarios.

adi1998
Messages
15
Reaction score
0
I've found this a very confusing thing:when we locate the second dark fringes above and below the central maxima,we divide the slit into four parts and claim that pairs of waves interfere destructively as the path difference would be wavelength/2.But what if we just divided it into two parts and claimed that two rays each from one half at equal distance would always interfere constructively with path difference=wavelength?
 
Science news on Phys.org
Where did you read/hear about this from?
 
Well, you uncovered the fact that the "simple subdivision of the gap" explanation is a very, very crude approximation. It gets the basic principle across that waves originating at different parts have different path lengths (and thus will interfere with each other), but of course, if you *really* want to calculate it, you have to consider each point of the gap as a wave source and add (well, integrate) the paths' interferences. That integral will actually give you the answer.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
9K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 34 ·
2
Replies
34
Views
4K
  • · Replies 8 ·
Replies
8
Views
21K
  • · Replies 1 ·
Replies
1
Views
3K