Sinusoidal Wave Frequency 500 Hz: Pi/3 Rad Apart

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A sinusoidal wave with a frequency of 500 Hz travels at a speed of 350 m/s, resulting in a wavelength of 0.70 m. To find the distance between two points differing by Pi/3 radians, the wave number k is calculated as 8.98. The angular frequency w is determined to be 3141 rad/s by converting the frequency to period. The approach involves using the equation y = Asin(kx - wt + Pi/3) to solve for the distance apart, although the amplitude is not needed for this calculation. The phase difference between two points a whole wavelength apart is 2π radians.
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A sinusoidal wave of frequency 500 Hz has a speed of 350 m/s.
(a) How far apart are two points that differ in phase by Pi/3 rad?

I was thinking that I need to use the equation y= Asin(kx-wt+pi/3)

I found the wavelength=0.70m

used this to find k=8.98

solved for w by converting the frequency to the period and using w=2pi/T to get w=3141 but I don't have amplitude.

I figured after plugging everything in and solving for x gives me the distnace apart. Is this the right approach?
 
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