Skateboarder with a mass of 150kg

  • Thread starter Thread starter roske
  • Start date Start date
  • Tags Tags
    Mass
AI Thread Summary
A skateboarder with a mass of 150 kg collides with a stationary steel dumpster, coming to a stop in 0.25 seconds from an initial velocity of 13 m/s. The rate of acceleration during the stop is calculated as -52 m/s². The force exerted on the dumpster is determined to be 7800 N, based on the change in momentum. The calculations confirm the relationships between time, acceleration, and change in velocity. The discussion emphasizes the application of physics equations to analyze the collision scenario.
roske
Messages
4
Reaction score
0
A skateboarder with a mass of 150 kg is traveling at a final velocity of 13m/s and collides with a steel dumpster. The dumpster does not move. The skateboarder comes to a stop at 0.25 seconds. What is his rate of acceleration as he stops? How much force does he exert on the dumpster?

Can someone help me please.
 
Physics news on Phys.org
Can you write down an equation for the relationship between time, acceleration and change in velocity?
 
Initial velocity= 13ms^-1
Final velocity= 0ms^-1
Time= 0.25s

A) Rate of acceleration = (V-U)/T = (0-13)/0.25 = -52ms^-2

B) Force exerted on the dumpster= F= (MV)/ T = (150*13)/0.25 = 7800N

I think?
 
That looks correct to me! Average acceleration is change in velocity divided by change in time. Force exerted is equal to the change in momentum.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top