Skier on a slope -- speed question

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To determine the skier's speed at points C and D, energy conservation principles can be applied, linking kinetic energy (KE) and gravitational potential energy (PE). The skier's mass is not necessary for this calculation, as the mass will cancel out in the equations. It is important to consider gravitational acceleration as 9.81 m/s². A triangle vector diagram can assist in visualizing the problem, but focusing on energy conservation is key to finding the solution. The discussion emphasizes using the homework template for clarity in future inquiries.
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Question: Beginning at rest from the top of the slope, what is the speed at C and at D?

I don’t understand how to solve this question without being given the skier’s mass, acceleration, time or angle.
I drew a triangle vector diagram with delta d1 using the distances given. And i made gravity positive downwards where g=9.8 m/s^2.
 

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Nayu said:
View attachment 238297 Question: Beginning at rest from the top of the slope, what is the speed at C and at D?

I don’t understand how to solve this question without being given the skier’s mass, acceleration, time or angle.
I drew a triangle vector diagram with delta d1 using the distances given. And i made gravity positive downwards where g=9.8 m/s^2.
Welcome to the PF.

Please do not delete the Template you are provided when starting a new schoolwork thread. It helps to organize your post to make it easier for us to help.

On your question, write down the relevant equations that relate the kinetic energy (KE) of the skier to their gravitational potential energy (PE). And how are KE and PE defined in terms of mass, speed, height, etc.?
 
Nayu said:
View attachment 238297 Question: Beginning at rest from the top of the slope, what is the speed at C and at D?

I don’t understand how to solve this question without being given the skier’s mass, acceleration, time or angle.
I drew a triangle vector diagram with delta d1 using the distances given. And i made gravity positive downwards where g=9.8 m/s^2.

Ahoihoi @ PF!

For future questions regarding homewrk please use the homework template.

Neglecting the friction you are able to solve the task without any more information - just apply energy conservation. And yes, consider ##g=9.81\,m/s##.

EDIT: ##g=9.81\,m/s^2## of course ... Thanks @berkeman
 
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