An 80 kg skydiver jumps from an altitude of 1000m and opens his chute at 200m
(a) The total retarding force on the diver is a constant 50.0N without his chute open, it is constant 3600N with his chute open. What will be the skydiver's speed when he reaches the ground?
E(total)=P.E. + K.E.
The Attempt at a Solution
Well, frankly I've gone through several methods and it's all become a big mess. It seems like a straight forward problem but I think I've gotten tunnel vision from it and am missing something obvious. I have a hunch I should be using PE and KE rather than the following methods, but this was all I could come up with.
I got a velocity (at 200m)=122 m/s doing this:
t= 8.34 (or -1.3... obviously time can't be negative)
V(final)=-170 m/s.... this does not seem right at all to me.
Any suggestions? I had tried using PE and KE to solve for it, but got lost along the way.