Sliding on a sliding hemisphere

AI Thread Summary
The discussion revolves around a physics problem involving a small mass sliding on a hemisphere while the hemisphere itself can move on a frictionless table. The user initially attempts to apply conservation of energy and momentum to derive the ratio of the masses M and m, but identifies mistakes in their calculations. They specifically note errors in their energy conservation equation and the condition for the small mass leaving the hemisphere's surface. After revising their approach, they express satisfaction in resolving the problem, highlighting the benefits of articulating the problem for clarity. The conversation emphasizes the importance of careful analysis in physics problem-solving.
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Homework Statement


A small mass m slides on a hemisphere of mass M and radius R is also free to slide horizontally on a frictionless table. An imaginary vertical line is drawn from the center of the hemisphere to its highest point, where the small mass is originally placed at rest. The angle A is the acute angle made by another imaginary line drawn from the small mass after it starts to slide down to the center of the hemisphere with the imaginary vertical line mentioned before. In other words, A= 0 originally. Given that cosA = k. Find the ratio of M/m.

Homework Equations


I'm not really sure.

The Attempt at a Solution


Here's what I did.

I imagine that the big mass moves at velocity V and the small mass with a tangential speed v after some time. Then using the conservation of energy I obtain,

mgR = \frac{1}{2}(M+m)V2 + \frac{1}{2}mv2EDIT: I just spot my mistake on the mgR thing.

Next I obtain the condition when the small mass just begins to leave the hemisphere's surface,

gcosA= v²/R

I think my mistake is the above.

I then obtain another equation using the conservation of momentum in the left-right direction,

mvcosA=(M+m)V

Then I substituted and rearranged all the stuff and got:

\frac{(k-1)}{k(2-k)}2 = M/m

But it doesn't look correct.

EDIT: I think I found the mistake in the conservation of energy part. But still do give hints on how to solve it.
 
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I just solved it. Anyway, typing the problem down again here sure does help in solving it by making you think hard again. :smile:
 
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