- #1
**bouncey!!**
- 13
- 0
so...do they/ don't they exist?
i don't think they do as they would have to be even with an even number of (odd*even) factor pairs.
And if you assume this number is in the form of 2p where p is odd and has only two (odd*even) facots pairs, it must have the factors (2*psqaured) and (p * 2p)
if is was slightly excessive;
x + 1 = 1 + 2 + psqaured + p + 2p
x = (p+1)(p+2
so another factor pair...
i don't think they do as they would have to be even with an even number of (odd*even) factor pairs.
And if you assume this number is in the form of 2p where p is odd and has only two (odd*even) facots pairs, it must have the factors (2*psqaured) and (p * 2p)
if is was slightly excessive;
x + 1 = 1 + 2 + psqaured + p + 2p
x = (p+1)(p+2
so another factor pair...