Small trig substitution problem.

AI Thread Summary
The discussion revolves around a trigonometric identity involving the expression sin^4(t)cos^2(t) + cos^4(t)sin^2(t) and its simplification to cos^2(t)sin^2(t). Participants suggest factoring out sin^2(t)cos^2(t) as a simpler approach to derive the identity. Initial attempts at substitution led to complex expressions that did not yield the desired result. Ultimately, the simpler factoring method proved effective, demonstrating the importance of looking for common factors in trigonometric problems. The conversation highlights the value of collaborative problem-solving in mathematics.
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Homework Statement



I was working on a problem set involving greens theorem and I came across this peculiar trig substitution. I was just wondering how it came about as I couldn't find anything like it on Wikipedia's page.

sin^4(t)cos^2(t) + cos^4(t) sin^2(t) = cos^2(t)sin^2(t)

The Attempt at a Solution


I tried using the basic's such as (cos^2(t))^2 = (1 - sin^2(t))^2

along with (sin^2(t))^2 = (1 - cos^2(t))^2

which after some substitution gives

cos^6(t) - cos^4(t) + sin^2(t)cos^2(t) + sin^6(t) - sin^4(t) + sin^2(t)cos^2(t)

Which is close to what I wanted, but I started to get the feeling that the path I was going down wasn't going to yield my identity. Can anyone shed some light?
 
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Hi ozone! :smile:

Did you try the simpler idea of taking sin^2t\cdot cos^2t out common? :wink:
Edit : Arrgh! multi-post :frown:
Mod note: not any more...
 
Last edited by a moderator:
ozone said:

Homework Statement



I was working on a problem set involving greens theorem and I came across this peculiar trig substitution. I was just wondering how it came about as I couldn't find anything like it on Wikipedia's page.

sin^4(t)cos^2(t) + cos^4(t) sin^2(t) = cos^2(t)sin^2(t)

The Attempt at a Solution


I tried using the basic's such as (cos^2(t))^2 = (1 - sin^2(t))^2

along with (sin^2(t))^2 = (1 - cos^2(t))^2

which after some substitution gives

cos^6(t) - cos^4(t) + sin^2(t)cos^2(t) + sin^6(t) - sin^4(t) + sin^2(t)cos^2(t)

Which is close to what I wanted, but I started to get the feeling that the path I was going down wasn't going to yield my identity. Can anyone shed some light?
How about:

\sin^4(t)\cos^2(t) + \cos^4(t) \sin^2(t) = \cos^2(t)\sin^2(t)\left(\sin^2(t)+\cos^2(t)\right) \ ?
 
Thanks sammy's that is definitely sufficient proof for me. DOH that was an easy one =d

edit: thanks infinitum too you would have pointed me in the right direction
 
ozone said:
Thanks sammy's that is definitely sufficient proof for me. DOH that was an easy one =d

edit: thanks infinitum too you would have pointed me in the right direction

Err, what SammyS and I said are exactly the same thing. I preferred not to elaborate :smile:
 
Infinitum said:
Hi ozone! :smile:

Did you try the simpler idea of taking sin^2t\cdot cos^2t out common? :wink:



Edit : Arrgh! multi-post :frown:

I second that motion. Always factor factor FACTOR !
 
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