1. The problem statement, all variables and given/known data determine the value of Beta for which the tension in cable B is as small as possible, then find the corresponding tension. Given Alpha = 5 degrees and the weight of the object is 12kN This is an image of it http://imageshack.us/photo/my-images/801/unledgsn.png/ 2. Relevant equations Fy=0 Fx=0 (at equilibrium) 3. The attempt at a solution Fx= -TAsin5 + TBcos(Beta) Fy=TAcos5 - TBsin(Beta) - 12 from Fx i get TA = (TBcos(Beta))/Sin5 and i plug it into Fy to get 12=TB(11.4cos(Beta)-sin(Beta)) but this doesnt answer my first question of what is the angle, only helps with part 2 of the question..