So, the conversion factor is 10^6.

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To convert from meters cubed to centimeters cubed, the conversion factor changes from 10^-2 to 10^6. This is because when cubing the conversion factor for linear measurements, you must cube both sides of the equation. Therefore, 1 meter equals 10^2 centimeters, and when cubed, it results in 1 cubic meter equaling 10^6 cubic centimeters. This highlights the significant difference in scale when dealing with volume conversions compared to linear measurements. Understanding this conversion is essential for accurate calculations in various applications.
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When going from meters cubed to centimeters cubed, what do you change from the normal 10 ^ -2?


Thank you for your time.
 
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Just think of it this way ...

1m=10^2cm

or

10^{-2}m=1cm
 
But what about when it is meters cubed to centimeters cubed? Isn't something different there?
 
Twilit_Truth said:
But what about when it is meters cubed to centimeters cubed? Isn't something different there?
1m=10^2cm

cubed ...

(1m)^3=(10^2cm)^3

which becomes

1m^3=10^6cm^3
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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