Originally posted by Artman
Something to consider:
If you have an attic, I have seen plans for a water heater that uses a fan to move attic air through a coil. Attics get pretty warm depending on the insulation arrangement. If the insulation is on the attic floor, the attic gets warm. If it's on the underside of the roof, the attic may not be too warm.
If you do have a warm attic, this kind of system can have two positive effects, cools the attic and warms the water in the coil. This may not provide enough heat to completely heat the water, but the combined effect of reducing air conditioning load, and preheating domestic water may allow for electric or gas backup for the water heating and still allow for savings.
This kind of system also works good for a swimming pool heater.
One needs to be careful with ideas like this since the costs can exceed the lifetime benefit. The problem is the heat exchange efficiency. The rate of heat transfer through a separating wall increases as the velocity, density, specific heat, and the thermal conductivity of the fluids increase. The state of the fluids inside and outside of the thermal conductor is also significant. For example, liquid to liquid transfers are more efficient that gas to liquid.
Here are some numbers from an old engineering book that I use; Refrigeration, Air Conditioning, and Cold Storage; by Gunther, 1969 [it was old when I got it]. This was long considered the bible of heat transfer applications.
For a well designed industrial heat exchanger, using clean copper pipes and with low rates of fluid flow [e.g. < 1 gpm liquid flow per foot of linear contact between the media and the copper pipes, with air moving by a low power fan - air to water transfers], we typically get something like 2 BTU per hr per sq. ft of contact per degree F – a best case scenario.
So if we use some typical 3/4" copper pipe, we get about 0.19 sq ft of contact per ft of pipe. We might expect a temperature differential of no more than 30 degrees F at the inlet, and 10 degrees at the outlet in order to be useful at the other end. So we can loosely assume an average of a 20 degree difference [not really but the error works in your favor]. Thus we get about 0.4 BTU per hr per linear foot of 3/4" pipe. The pipe size was chosen to make the system practical. Smaller pipe requires greater length; stay tuned.
Next, 1 BTU per hr is about 0.29 watts [CRC]; which yields about 0.12 watts per linear foot of exchange. So in order to rival the contribution of a 100 watt light bulb, we need at least 830 feet of 3/4” copper tubing. The current price of type L copper [common] is about $2.25 per foot. So for only $1,900.00, just for the pipe mind you, you still need a pump, controls, wiring, a fan, these need to then be powered which may take more than 100 watts, you can have the heat of a 100 watt light bulb for about half the day.
At ten cents per KWH, this would only require 43 years to pay for the pipe.
My point: If these types of systems are to be of use they must be properly engineered.