# Solution concentration and ppm

Hi all, I have 2 short questions, that have caused me trouble in my study.

Firstly,
What is generally considered to be a highly concentrated solution?
eg. 250mL acid in 10L water.
This is 250E-3/10 = 0.25/10 = 0.025 M.
Would that be considered a concentrated solution? as it seems very low ...

Secondly,
In a sample of ground water, iron in the form of Fe2+ was found to have concentration 9.00E-3 M. Assuming the density of water is 1.00 gmL-1, what is the concentration of Fe2+ in ppm?
Now I'm not really sure what is going on here, but given the Fe2+ has a molar concentration of 9.00E-3, surely there is a way to convert that to gL-1 and then to mg/kg (ppm solute/solvent form)?
am i correct?
(just need to be lead on the right track there ...)

cheers
Steven

danago
Gold Member
Hi all, I have 2 short questions, that have caused me trouble in my study.

Firstly,
What is generally considered to be a highly concentrated solution?
eg. 250mL acid in 10L water.
This is 250E-3/10 = 0.25/10 = 0.025 M.
Would that be considered a concentrated solution? as it seems very low ...

Hey To calculate the molarity of the final solution, youre going to need to know what the concentration of the original 250mL acid solution is, so you can find how many moles in the final solution.

Hey sup

The question for the first part im working on doesnt actually state any other values for me to work with. It states; "Household vinegar can be produced by adding 250mL of acetic acid to 10L of pure water. Which of the following best describes the acetic acid".
The answer is; "a concentrated solution of weak acid"
Now what I worked out before (0.025M) I thought was pretty low for a high concentration.
Any ideas?

part a i got fine now... just another stupid misunderstanding ....

any other suggestions for part b?

danago
Gold Member
For the second question, you are told the concentration of Fe+2 in mol/L. You should start by converting that to a concentration in g/L, and then g/mL. See if you can go from there.

[Fe2+]=0.009
=0.50265 g/L
=0.50265 x 10^3 mg/L
=502.65 mg/L
therefore
502.65 ppm

cheers

chemisttree