Solution to Cardano's Algebra Problem: Divide 10 into 2 Parts

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The discussion revolves around a problem from Cardano's Algebra, specifically dividing the number 10 into two parts such that their product equals 40. It is established that the equations x + y = 10 and xy = 40 lead to a quadratic equation, which, upon solving, reveals that there are no real solutions. The conversation highlights that while real solutions do not exist, complex solutions may be possible, as Cardano acknowledged the concept of imaginary numbers, albeit without fully understanding them. The conclusion drawn is that Cardano's original problem does not have a solution in the real number system, but may have solutions in the complex realm. The discussion emphasizes the historical context of Cardano's understanding of numbers and their properties.
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It's from Cardano's Algebra book.

Divide 10 into 2 parts whose product is 40.

Is this just called Algebra? I've never seen problems like this before. How would you begin solving it? Thanks.
 
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Call the two parts x and y. Then in my understanding the question asks to determine x and y such that x+y=10 and xy=40. Of course there is no reason why such numbers should exist.
 
Hint: In the Reals there may be no reason, but in the Complexes you may find something.
 
If there are such numbers, then they can be written as x and 10 - x. Their product is 40, so we have the equation:

<br /> x (10 - x) = 40<br />

This is a quadratic equation. It reduces to the normal form:

<br /> x^{2} - 10 x + 40 = 0<br />

Completing the square of the quadratic trinomial, we get:

<br /> (x - 5)^{2} + 15<br />

This cannot be less than 15, so there are no such real numbers.
 
Dickfore said:
If there are such numbers, then they can be written as x and 10 - x. Their product is 40, so we have the equation:

<br /> x (10 - x) = 40<br />

This is a quadratic equation. It reduces to the normal form:

<br /> x^{2} - 10 x + 40 = 0<br />

Completing the square of the quadratic trinomial, we get:

<br /> (x - 5)^{2} + 15<br />

This cannot be less than 15, so there are no such real numbers.

Which is not to say that there aren't solutions to the equation. They just don't happen to be real.
 
Mark44 said:
Which is not to say that there aren't solutions to the equation. They just don't happen to be real.

Which means his original problem has no solution. He wasn't looking for any numbers, he was looking for 10 to be divided into two parts.
 
And these parts are not a priori restricted to be positive.
 
Dickfore said:
Which means his original problem has no solution. He wasn't looking for any numbers, he was looking for 10 to be divided into two parts.

Pere Callahan said:
And these parts are not a priori restricted to be positive.
Or even real.

According the the Wikipedia article (http://en.wikipedia.org/wiki/Gerolamo_Cardano) I glanced at yesterday, Cardano "acknowledged the existence of what are now called imaginary numbers, although he did not understand their properties".
 
Mark44 said:
Or even real.
That's what I meant to write.
Mark44 said:
According the the Wikipedia article (http://en.wikipedia.org/wiki/Gerolamo_Cardano) I glanced at yesterday, Cardano "acknowledged the existence of what are now called imaginary numbers, although he did not understand their properties".
Then the question is, if he didn't understand their properties, did he know how to multiply complex numbers? He could certainly, without any knowledge write down an expression for x and y involving roots of negative numbers. And complex numbers written in the form of roots of negative numbers are easily multiplied so he could easily check that his result was correct.
 
  • #10
Pere Callahan said:
Then the question is, if he didn't understand their properties, did he know how to multiply complex numbers? He could certainly, without any knowledge write down an expression for x and y involving roots of negative numbers. And complex numbers written in the form of roots of negative numbers are easily multiplied so he could easily check that his result was correct.

He understood how to multiply them and add them, just denied that they were meaningful.
 
  • #11
Mark44 said:
Or even real.

Please show where the OP allowed for this possibility?
 
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