Solution to the Klein Gordon Equation

benk99nenm312

Hey guys, I was reading up on the Klein Gordon equation and I came across an article that gave a general solution as: $$\psi$$(r,t)= e^i(kr-$$\omega$$t), under the constraint that -k^2 + $$\omega$$^2/c^2 = m^2c^2/$$\hbar$$^2, forgive my lack of latex hah.

Through Euler's law this does give a solution tantamount to cos(kr-$$\omega$$t)+isin(kr-$$\omega$$t).

My question is simply.. is this valid? I ask because if you were to integrate the square over an interval you should get a probability, however the imaginary term will carry through from the de Moivre formula. I'm terribly confused.

Thanks guys!

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tiny-tim

Homework Helper
hey benk99nenm312! … if you were to integrate the square over an interval you should get a probability, however the imaginary term will carry through from the de Moivre formula. I'm terribly confused.
no, the probability is ψ*ψ, not ψ2 benk99nenm312

hey benk99nenm312! no, the probability is ψ*ψ, not ψ2 Omg wowww, lol. Thank you hah.

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