dy/dx + 0.8 y = 0.6 e ^-(0.6+0.8) , y(0) = 1
Solve this ordinary differential equation subject to the given condition using exact methods and evaluate the solution y for x = 0.0 (0.05) 0.5, i.e from x = 0 to x = 0.5 in steps of 0.05).
Hi, am pretty hopeless at ODEs, I do not even understand what the question means. Would someone be able to put it simply. I am not sure what exact methods are. Is this to do with runge kutta?
Any help would be great thanks!