Solve Calculation: Mass of Ice Melted with Carrots at 100°C

  • Thread starter Thread starter fabbo
  • Start date Start date
  • Tags Tags
    Confused
AI Thread Summary
To calculate the mass of ice melted by the carrots, first determine the energy transferred to the carrots using the specific heat capacity formula, noting that their initial temperature is 100°C. Since some ice remains after thermal equilibrium, the final temperature of the carrots must be lower than 100°C. The specific latent heat of fusion for water is essential for calculating how much ice melts. Understanding these principles allows for the correct application of thermodynamic equations to solve the problem. The discussion concludes with the user expressing clarity on the calculation process.
fabbo
Messages
31
Reaction score
0
Ok, I had these questions for homework and had no problems with them except this one.

A variety of carrots has a specific heat capacity of 3700J/Kg/K. A saucepan of boiling water is used to raise the temperature of 825g of these carrots to 100 C. The carrots are then drained and immediately transferred to a large amount of ice and water in a plastic bowl. some of the ice still remains when the carrots achieve thermal equilibrium with the ice/water mixture. The specific latent heat of fusion of water is 330kJ/Kg. Calculate the mass of ice that melts during this process.


The only way I know how to work it out is by first calculating the energy put into the carrots using the specific heat capacity equation but we are not given a temperature rise. Should I assume the rise is 100 C. Any help is gratefully received. X
 
Physics news on Phys.org
You are told that the carrots--just before they are transferred to the bowl of ice/water--were at a temperature of 100 C. That's the initial temperature of the carrots. Since some ice remains after equilibrium is reached, what must be the final temperature of the carrots?
 
Doc Al said:
You are told that the carrots--just before they are transferred to the bowl of ice/water--were at a temperature of 100 C. That's the initial temperature of the carrots. Since some ice remains after equilibrium is reached, what must be the final temperature of the carrots?

oh i get it now - thank you!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top