Solve Cauchy-Riemann Equations with Polar Coordinates

  • Thread starter Thread starter y.moghadamnia
  • Start date Start date
  • Tags Tags
    Coordinate Polar
y.moghadamnia
Messages
23
Reaction score
1
hey, I know this might be abit silly, but u know the cauchy-reimann formula for a complex function to be diffrentiatable? here is a link to what I am talking about:
http://en.wikipedia.org/wiki/Cauchy-Riemann_equations
my question is: how do I write it in polar coordinates?:redface:
 
Physics news on Phys.org
The answer to your question is on the page you linked to, pretty near the end, under "Other Representations."
 
yeah, I know that. my question is how to change the diffrentiates from respect to x to for example r and theta. I know they might be easy using the chain rules, but I always get so confused on this and thought maybe sb could help me write it
 
You do use the chain rule. Give it a shot and show us what you come up with.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top