Solve cosxcos(-x) - sinxsin(-x) = 1

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The equation cosxcos(-x) - sinxsin(-x) simplifies using the identities cos(-x) = cos(x) and sin(-x) = -sin(x). Substituting these values leads to cos(x)^2 + sin(x)^2 = 1, which is a fundamental trigonometric identity. The discussion also touches on the angle addition formula, noting that the left-hand side resembles cos(x + (-x)). Ultimately, the simplification confirms the identity holds true, illustrating the relationship between cosine and sine functions. The problem is resolved by recognizing these trigonometric properties.
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cosxcos(-x) - sinxsin(-x) = 1

I know I'm making it harder than it is, but I can't seem to figure it out.
Any help would be appreciated.

RaveN
 
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cos(-x)=cos(x). sin(-x)=-sin(x).
 
When I plugged those in then I get cosx2 - sinx2 = 1 and then I get completely lost.
 
When I plug them in I get cos(x)^2+sin(x)^2=1. There are two minus signs associated with the sin(x)^2.
 
Because it's -sin to begin with. I knew I was making it too hard. Thanks.
 
Another way: isn't the l.h.s. in the form of an angle addition formula?
 
Not with the correct signs! It's cos2(x)+ sin2(x)!
 
It is cos(x+(-x)). That is another way to do it.
 
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