Solve Current Divider Rule for Resistor Currents w/ R & i

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The discussion focuses on applying the current divider rule (CDR) to find the current through three resistors connected in parallel, specifically with resistances of 4 ohms, 2 ohms, and an unknown resistor R. The poster initially struggles with the correct application of the CDR formula, questioning their derived expressions for the currents through each resistor. They express confusion about the correct formulation, particularly in how to incorporate the total resistance and the individual resistances into the calculations. The conversation emphasizes the importance of understanding the voltage across the parallel resistors to accurately calculate the current through each one. Ultimately, the discussion seeks clarity on the effective resistance of the parallel combination and the resulting current values.
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Homework Statement



Three resistors with resistance 4 ohms, 2 ohms, and R are connected in parallel. There is a total current i through the network. Find the current through each resistor in terms of R and i.

Ignore the 4 ohms and 2 ohms for now I just need help with the CDR formula...Thanks

Homework Equations



i_0 = i_1 + i_2 + i_3

V = V_1 + V_2 + V_3

V_n = i_n * R_n


The Attempt at a Solution



Following the current divider rule I came to the "answer":

i_n = i_0(R_total/R_n)

so for example

i_1 = i_0((R_1 + R_2 + R_3)/R_1)

However my example problem states that the answer should be:

i_1 = i_0(R_2/(R_1 + R_2 + R_3))...?
 
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Wait...is this correct?

i_1 = i_0(R_2 + R_3/R_total)

i_2 = i_0(R_3/R_total)

i_3 = i_0(0/R_total) = 0 because there are no resistor to the right of R_3
 
What's the effective resistance of the parallel combination of three resistors? Call them R1, R2, R3.

Since the total current through the parallel group given as i, what's the voltage across all three? And, given the voltage across all three, you are now in a position to calculate the current though each, right?
 
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