Solve Diff. Eq. w/ Initial Conditions: y' + 2y = te^-2t | Homework Help

dwilmer
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Homework Statement



Solve the differential equation: y' + 2y = te^-2t with initial conditions y(1) = 0?
Please show me what I am doing wrong... (or right).. also please don't show me shortcut i need to know where I am going wrong thanks.



Homework Equations





The Attempt at a Solution



first i multiplied whole equation by integrating factor e^2t (e^integral(2) = e^2t)
after rearranging this gave me

e^2t(y) = integ te^-2t * e^2t

i then simplified RHS to get:
e^2t(y) = integ t

then i integrated RHS to get

e^2t(y) = (t^2)/2 + c

then i isolated y to get:

y = ((t^2)e^-2t) / 2 + ce^-2t

then i applied the initial condition y(1) = 0
this gave me

0 = e^-2 / 2 + ce^-2

then i multiplied equation by 2

0 = e^-2 + ce^-2

then i factored out e^-2

0 = e^-2 (1 + c)

then i reasoned that c must = 1 and put this back into the explicit equation

y = ((t^2)e^-2t) /2 + (1) e^-2t

is this correct? the book answer says y = (t^2 -1) e^-2t /2

THANKS FOR ANY HELP
 
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Look for a couple of arithmetic mistakes after you used the initial condition y(1)=0.
 


dwilmer said:

Homework Statement



Solve the differential equation: y' + 2y = te^-2t with initial conditions y(1) = 0?
Please show me what I am doing wrong... (or right).. also please don't show me shortcut i need to know where I am going wrong thanks.



Homework Equations





The Attempt at a Solution



first i multiplied whole equation by integrating factor e^2t (e^integral(2) = e^2t)
after rearranging this gave me

e^2t(y) = integ te^-2t * e^2t

i then simplified RHS to get:
e^2t(y) = integ t

then i integrated RHS to get

e^2t(y) = (t^2)/2 + c

then i isolated y to get:

y = ((t^2)e^-2t) / 2 + ce^-2t

then i applied the initial condition y(1) = 0
this gave me

0 = e^-2 / 2 + ce^-2

then i multiplied equation by 2

0 = e^-2 + ce^-2

then i factored out e^-2

0 = e^-2 (1 + c)

then i reasoned that c must = 1 and put this back into the explicit equation
Then you reasoned wrong. c is not equal to 1.

y = ((t^2)e^-2t) /2 + (1) e^-2t

is this correct? the book answer says y = (t^2 -1) e^-2t /2

THANKS FOR ANY HELP
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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