Solve ∫(e^x)/(√4-e^(2x)) w/ arcsin of x

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SUMMARY

The integral ∫(e^x)/(√4-e^(2x)) can be simplified by factoring out the constant from the square root. Specifically, to transform √4 into 2, one can factor out 4 from the expression, allowing the equation to be rewritten as 2√(a+b/4). This approach utilizes the property that √(ab) = √a * √b, which is essential for simplifying integrals involving square roots. The discussion emphasizes the importance of proper algebraic manipulation in solving integrals.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with algebraic manipulation of square roots
  • Knowledge of the properties of logarithmic and exponential functions
  • Basic understanding of trigonometric functions, specifically arcsin
NEXT STEPS
  • Study the properties of integrals involving exponential functions
  • Learn techniques for simplifying square roots in algebraic expressions
  • Explore the application of arcsin in calculus problems
  • Investigate advanced integration techniques, such as substitution and integration by parts
USEFUL FOR

Students studying calculus, particularly those tackling integration problems involving exponential functions and square roots, as well as educators seeking to clarify algebraic manipulation techniques.

ralfsk8
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Homework Statement



∫(e^x)/(√4-e^(2x))


Homework Equations



arcsin of x

The Attempt at a Solution



I know how the problem should be solved and have an idea of what the final answer will be. My only question is, how would I take out the four from the square root, in order to make it a 1? Can I just pull out 1/4?

Thank You
 
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ralfsk8 said:

Homework Statement



∫(e^x)/(√4-e^(2x))


Homework Equations



arcsin of x

The Attempt at a Solution



I know how the problem should be solved and have an idea of what the final answer will be. My only question is, how would I take out the four from the square root, in order to make it a 1? Can I just pull out 1/4?

Thank You

Yep. If you have \sqrt{4a+b} then in order to make the coefficient of a equal to 1, just factor out a 4 and then use the rule that \sqrt{ab}=\sqrt{a}\sqrt{b} so we'll have

\sqrt{4a+b}
=\sqrt{4(a+b/4)}
=\sqrt{4}\sqrt{a+b/4}
=2\sqrt{a+b/4}
 

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