Solve Equation of Line with Slope of 1¼

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Homework Help Overview

The discussion revolves around understanding how to work with a slope expressed as a mixed number, specifically 1¼, in the context of the equation of a line.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the conversion of a mixed number into an improper fraction as a means to facilitate calculations involving slopes.

Discussion Status

Some participants have provided insights on converting mixed numbers to improper fractions, while others express their understanding and appreciation for the clarification. The discussion appears to be progressing with various interpretations of the conversion process being explored.

Contextual Notes

There is a focus on the method of converting mixed numbers, and participants are engaging with the concept without a complete resolution of the original problem regarding the equation of the line.

tehmatriks
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Homework Statement


i just want to know how i go about it when the slope contains a whole number and a fraction, i.e. 1¼

Homework Equations


y - y1 = m(x - x1)


The Attempt at a Solution

 
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Change the number into an improper fraction. Do you know how to do that?

For instance,
[tex]2\frac{1}{3} = \frac{7}{3}[/tex]
 
i didn't no, but from the looks of it you multiply the whole number by the denominator and add the numerator

so i got it, much appreciated
 
tehmatriks said:
i didn't no, but from the looks of it you multiply the whole number by the denominator and add the numerator

so i got it, much appreciated

Another way to think of it:

"Two and one-third" = [itex]2+\frac{1}{3}[/itex] ("and" typically means addition)

Think of a fraction with a denominator of 3 that is also equal to 2.

[tex]\frac{6}{3}+\frac{1}{3}=\frac{7}{3}[/tex]

This is probably a bit more work than what's necessary, but I find it much more interesting. :biggrin:
 

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