Solve for Constant Torque: 75g-cm2 to Spin Yo-Yo to 300 rev/min in 1s

AI Thread Summary
To determine the constant torque required for a yo-yo with a moment of inertia of 75.0 g-cm² to reach 300 rev/min in one second from rest, the angular acceleration must first be calculated. The formula used is angular acceleration equals the change in angular velocity divided by time. After calculating the angular acceleration, it is multiplied by the moment of inertia to find the torque. The final answer for the required torque is 2.36 x 10^-4 kg*m²/s². This approach confirms the correct application of physics principles for solving the problem.
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Homework Statement


A yo-yo has a moment of inertia of 75.0 g-cm2 about its rotation axis. What is the constant torque required to make it spin to 300 rev/min in one second, starting from rest?

Homework Equations


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= Iα

The Attempt at a Solution


I was thinking since the question is asking for constant torque, angular acceleration would also have to be constant. Therefore, I would just find angular acceleration (using (ω(t) - ω0)/(t2-t1)) then multiply that angular acceleration by the moment of inertia. Is that correct thinking?
 
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Yes, your thinking is correct. Be careful with the units.
 
What did you get as your answer for this?
 
cat__lover said:
What did you get as your answer for this?
2.36 x 10^-4 kg*m^2/s^2
 
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