Solve for Golf Ball Angle and Velocity: 300m Hole with/without Air Resistance

  • Thread starter Thread starter GoDzSoLDiiEr
  • Start date Start date
AI Thread Summary
To determine the angle and initial velocity required for a golf ball to reach a hole 300 meters away, calculations must be made for both scenarios: with and without air resistance. The problem acknowledges that there are infinite pairs of angle and velocity values that can achieve this distance. In an ideal environment without air resistance, the optimal launch angle is typically around 45 degrees for maximum range. However, when factoring in air resistance, the angle and velocity will differ, requiring more complex calculations. Understanding these dynamics is crucial for accurately solving projectile motion problems in physics.
GoDzSoLDiiEr
Messages
2
Reaction score
0

Homework Statement


What is the angle and inital velocity required for a golf ball to go in a hole 300m away?
/\Dx= 300m
Find two answers; one in an environment with air resistance, and one w/o air resistance.


Homework Equations


...?



The Attempt at a Solution


...?
 
Last edited:
Physics news on Phys.org
Last edited:

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Golf club 🏌️and ball ⛳ impulse problem
Replies
19
Views
2K
Calculating the Impact Speed of a Bullet Fired Straight Up
Replies
6
Views
4K
Find the average force of a golf club on a golf ball
Replies
9
Views
6K
Free falling ball with and without air resistance
Replies
3
Views
2K
Calculating Force Applied to Golf Ball by Club with Limited Data
Replies
6
Views
7K
Projectile motion of a cannon ball versus time
Replies
15
Views
2K
Projectile motion when you are only given time and range
Replies
21
Views
3K
How does air resistance affect a ball's acceleration?
Replies
8
Views
8K
Projectile Motion: Angle & Range with Air Resistance and Wind
Replies
4
Views
2K
Final velocities with the inclusion of air resistance
Replies
4
Views
2K

Hot Threads

Recent Insights

Back
Top