Solve for Req with T to Delta Transform

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SUMMARY

The discussion focuses on calculating the equivalent resistance (Req) in a circuit using both series and parallel resistor combinations, specifically addressing the transformation from a T to a delta configuration. The user successfully calculated Req as 32.5 ohms using the original configuration but encountered difficulties after attempting to redraw the circuit. The confusion arose from misapplying the parallel resistor formula and overlooking the placement of the 25-ohm resistor in the delta transformation. The correct approach requires careful attention to the circuit layout and resistor connections.

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  • Understanding of series and parallel resistor combinations
  • Familiarity with T to delta transformations in circuit analysis
  • Knowledge of Ohm's Law and basic electrical principles
  • Ability to redraw and analyze circuit diagrams accurately
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  • Study T to delta transformation techniques in circuit theory
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  • Learn about circuit simulation tools like LTspice for visual verification
  • Review common mistakes in resistor combination calculations
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Electrical engineering students, circuit designers, and anyone involved in analyzing and solving electrical circuits will benefit from this discussion.

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Homework Statement


Find Req in the given circuit
upload_2016-9-26_13-10-23.png


Homework Equations


Series: req = r1+r2...
parallel: 1/req = 1/r1 + 1/r2 ...

The Attempt at a Solution


Without redrawing the circuit I do:
12||60 = 10
10+20 = 30
30 || 30 = 15
15+10 = 25
25||25 = 12.5
12.5+15+5 = 32.5 = Req
This is the correct answer.

upload_2016-9-26_13-10-3.png

However if I redrew the T to a delta I no longer can get the right answer.
108 || 0 = 0
(36 || 30) || (180 || 10) = 6
6||25...
and so on

Where am I going wrong in my logic? Am I not allowed to do this sort of transformation on this problem?
 

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zr95 said:
(36 || 30) || (180 || 10) = 6

Why is the 180 in parallel with the 10?
 
I completely looked over the 25 ohm resistor when I did that. Thanks.
 

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