Solve Force on Wheaties Box from Cheerios Box: Mass, Friction, & Force

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To solve for the force on the Wheaties box from the Cheerios box, start by applying Newton's Second Law to the system of both boxes. The total force applied is 12 N, with frictional forces of 2.0 N on the Cheerios box and 3.5 N on the Wheaties box. Calculate the net force acting on the system by subtracting the total friction from the applied force. Use the masses of both boxes to find the acceleration, then apply this acceleration to determine the force exerted on the Wheaties box. A free body diagram for each box can help visualize the forces involved in the calculations.
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Homework Statement


A box of Cheerios (mass mC = 1.1 kg) and a box of Wheaties (mass mW = 2.9 kg) are accelerated across a horizontal surface by a horizontal force applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2.0 N, and the magnitude of the frictional force on the Wheaties box is 3.5 N. If the magnitude of F is 12 N, what is the magnitude of the force on the Wheaties box from the Cheerios box?



Homework Equations


Fs,max=UsFn
fk=UkFn
F=ma
Fn=mg

The Attempt at a Solution


I'm not entirely sure how to set up this equation, I know F= m1(Ff)-m2(Ff) ... ? Or something along those lines. I'm not sure where to begin really.
 
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Draw a free body diagram of two-box system and put in all the forces that you know are there. Use Newton's Second Law to find the acceleration. Then draw a free body diagram of just the Wheaties box.
 
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