Solve Harmonic Problem: Find Bullet Speed Before Impact

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To solve the problem of finding the bullet's speed before impact, the conservation of momentum principle is essential. The user calculated the combined mass of the bullet and block as 0.625 kg and used the formula V = A√(k/m) to find the velocity after impact, resulting in 22.26 m/s. However, they are struggling to relate this back to the bullet's initial speed. The correct approach involves applying the conservation of momentum equation, which states that the momentum before impact equals the momentum after impact. The final goal is to determine that the bullet's speed before impact is 557 m/s.
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Hi! I've been working on this problem for a while, subtracting this and that.. but i can't get the answer which is 557m/s. Help would be greatly appreciated! Thanks in advance ><

1. A 25.0g bullet strikes a .600kg block attached to a fixed horizontal spring whose spring constant is 6.70x10^3 and sets it into vibration with an amplitude of 21.5cm. What is the speed of the bullet before impact if the two objects move together after impact?


2. V=A\sqrt{k/m}



3. I used the equation above, adding the masses together (.625kg). I got the velocity to be 22.26m/s... but now i can't figure out how to get the speed of the bullet.
 
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