Solve Impulse & Change in Momentum of Golf Ball

AI Thread Summary
The discussion revolves around calculating the impulse and change in momentum of a golf ball struck by a golf club. The impulse delivered to the golf ball is calculated using the formula impulse = force x time interval, resulting in an impulse of 40 Ns (Newton-seconds). The change in momentum of the golf ball is equal to the impulse, confirming that it is also 40, though typically measured in different units. Participants emphasize the importance of understanding the units involved in these calculations. Ultimately, both impulse and change in momentum are confirmed to be equivalent in this scenario.
vandorin
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Homework Statement


1.) A golf club strikes a golf ball. The club exers an 800N force for .05s. What is the impulse delivered to the golf ball?
2.) What is the change in momentum of the golf ball in the previous question?

Homework Equations



impulse = force x time interval

The Attempt at a Solution


I got the first question, but put it on here since it is relevant to the second question. I got 40 for the first question (I don't know the units, so if someone could tell me that would be cool :)) and also i have no idea what the second one would be. I would think it would just be 40?
 
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vandorin,

Think units:
What is force measured in?
What is time measured in?

Multiply these two together and you have your answer.

Impulse does indeed equal the change in momentum, but momentum changes are commonly measured in a different unit:

With the same procedure as before analyse:

momentum = mass x velocity
 
astrorob said:
vandorin,

Think units:
What is force measured in?
What is time measured in?

Multiply these two together and you have your answer.

Impulse does indeed equal the change in momentum, but momentum changes are commonly measured in a different unit:

With the same procedure as before analyse:

momentum = mass x velocity

So the answer to the last problem is 40? just with a different unit?
 
That is true.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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