Solve Impulse-Diffy eq. Homework: y''+y=δ(t-2π)cos(t), y(0)=0, y'(0)=1

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Homework Statement


y''+y=\delta (t-2\pi )cos(t)
y(0)=0,y'(0)=1


Homework Equations





The Attempt at a Solution


The left side is (s^2+1)Y(s)-1=RHS

My problem is the fact that cosine is being multiplied by the delta function. I put it in the form of an intergral but I don't know what to do from there.
 
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Well, good! Delta functions usually make integrals trivial. What integral did you get?
 
hmm, i don't know what is this question, may i know, what topic should i study for this question?
 
Differential Equations -Laplace transforms

OHHHH waitttt does the delta function just determine the bound of my intergral?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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