Solve Kinematics: Find Time of Fall for Object Dropped at 12 m/s

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To determine the time of fall for an object dropped with an average velocity of 12.0 m/s, it's important to recognize that the average velocity occurs at the midpoint of the motion. The discussion highlights confusion around the appropriate equations to use for this calculation. A reminder is given about the necessity of using a homework template to avoid deletion of the question. Additionally, there is a request for the total distance formula to assist with another problem. Clear understanding of kinematic equations is essential for solving these types of physics problems.
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its kinda confusing how to write it out but here i go.

you will note from questions 13 and 14 that the average velocity occurs at the mid-time of the motion. using this, determine the time of fall when an object is dropped if the average velocity of the falling object was 12.0 m/s.

i got 6.0 for the average velocity in the question but i don't know what equation i use to figure this question out. please help me X]
 
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Well, what did you find out in questions 13 and 14?

Incidentally, what happened to the homework template? Your question is at risk of being deleted if you do not use the template and/or show some work.
 
nvmdd i got help in class.

i have another question now i forgot the total distance formula and i need it to figure out my package. can someone leme know?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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