Solve Kinematics Problem: Horizontal Displacement

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The discussion focuses on solving a kinematics problem involving horizontal displacement. The user assumed there was no vertical component of velocity at the lowest point of the ball's trajectory, which aligns with scoring guidelines. They used relevant equations to calculate initial velocity, time, and horizontal displacement, confirming their calculations with provided scoring guidelines. Despite their confidence in the calculations, they express confusion over potential errors in their approach. The overall consensus is that the calculations seem correct, but further clarification may be needed.
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Homework Statement


I had a problem with e
http://img717.imageshack.us/img717/755/captureso.jpg
http://img34.imageshack.us/img34/1149/capture2vp.jpg

Homework Equations



see below

The Attempt at a Solution



So I assumed that there was no y component of velocity once the ball reaches it's lowest point. I believe this to be a very legit assumption. Even the scoring guidelines made this assumption.

The next thing that I did was use the velocity naught equation below that incorpates the velocity the acceleartion and the time in order to solve for the time

i didn't know the velocit though so i solved it using the equation velocity squared equation that incorporates the velocity naught the acceleration and the displacement which i knew all the terms and solved for the final velocity

i then solved for the time

i was then able to solve for the horizontal displacement sense the step before asked me to solve for the velocity naught in the x direction

The scoring guidelines confirmed my value i used for the horizontal velocity

http://img44.imageshack.us/img44/5169/capturej.jpg
http://img502.imageshack.us/img502/8854/capture2fc.jpg
http://img37.imageshack.us/img37/4259/capture3fo.jpg
http://img686.imageshack.us/img686/9018/captureym.jpg

Homework Statement


Homework Statement



so i really do not see what I'm doing wrong here...
 
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Your calculation appears to be correct.
 

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