Solve Kinematics Problem: Rocket Powered Sledge Speed in 60m Section

AI Thread Summary
A rocket-powered sledge accelerates at 35 m/s² over a 60m section in 1.6 seconds, prompting a discussion on calculating initial and final speeds. The equation x = ut + 1/2at² is suggested for finding the initial speed (u) and final speed (v). Participants express confusion over their calculations, with one claiming to have obtained incorrect values of 65.5 for u and 121.5 for v, while another suggests the correct values should be 9.5 for both speeds. The conversation emphasizes the importance of correctly rearranging the formula and learning from mistakes in the calculation process. Overall, the correct approach and understanding of the equations are crucial for solving the kinematics problem accurately.
ella_101
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Homework Statement



A rocket powered sledge accelerates at 35ms-2 and takes 1.6s to pass through a 60m section of a test track. Find the speed at which it entered the section what was its speed when it left?

Homework Equations



I think this is the equation to use x=ut + 1/2at2 and than use a=v-u/t to get v ?


The Attempt at a Solution



a= 35m/s
t= 1.6s
u=?
v=?
x= 60m

I got weird answers so there's no point putting them up!

please show your working

thanks
 
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ella_101 said:

Homework Statement



A rocket powered sledge accelerates at 35ms-2 and takes 1.6s to pass through a 60m section of a test track. Find the speed at which it entered the section what was its speed when it left?

Homework Equations



I think this is the equation to use x=ut + 1/2at2 and than use a=v-u/t to get v ?


The Attempt at a Solution



a= 35m/s
t= 1.6s
u=?
v=?
x= 60m

I got weird answers so there's no point putting them up!

please show your working

thanks

What exactly do you mean by a weird answer? Please put workings up, because your method seems right.
 
when i make 'u' the subject of the forumal i got 65.5 ( which is wrong) and for 'v' I got 121.5

I think my teacher said the answer was 9.5 for u and v i don't know,

what did you get ?
 
I know its an 'easy' question but i think i am just getting the equation wrong
 
ella_101 said:
when i make 'u' the subject of the forumal i got 65.5 ( which is wrong) and for 'v' I got 121.5

I think my teacher said the answer was 9.5 for u and v i don't know,

what did you get ?

Teacher is right, just remember that experience is the best teacher so by making this mistake and figuring out where you made it you've learned more, than me simply showing you the solution.

If you want you can show me you workings step by step, but as far as I can tell your eq is right your just calculating it incorrectly.How did you get 65.5?
 
okay,

x= ut + 1/2 at2

rearranged to give;

u= 1/2at2 + x/t ( this is were I think I am going wrong , rearranging it?)

than just plug in the numbers. = 65.5

OR
alternatively you can 'show' your working out=)
 
Alternatively, I found you can use simultaneous equations:
(v+u)/2=s/t...So, v+u=75 (i)
Also, v=u+at...So, u=v-56 (ii)
Now, we have 2v-56=75, and v=65.5...u=9.5
That's a simpler, but more bothersome method...
 
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Your transposition is a little faulty... If s=ut+1/2at^2...Then u = (s-1/2at^2)/t...What you found was your final velocity, v...Since, s=vt-1/2at^2...v=(s+1/2at^2)/t...Go back over your steps in rearranging the equation, you'll see the mistake.
 
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