Solve Light Transmittance Homework: Index Refraction of n=1.5

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The discussion focuses on calculating the fraction of light transmitted through two transparent plastic disks with an index of refraction of n=1.5, given a wavelength of 5000 angstroms. The reflectivity equation was initially misapplied, but the correct formula is identified as R = ((n1 - n2)/(n1 + n2))^2, resulting in a reflectivity of 4%. Consequently, 96% of the light is transmitted through each disk. The conversation also highlights the importance of considering multiple interfaces when calculating total transmission. Overall, the key takeaway is that the thickness of the disks is less significant than the number of interfaces involved in the transmission calculation.
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Homework Statement


Light of wavelength 5000 angstroms is incident normally on a series of two transparent plastic disks separated by a distance large compared with the wavelength. If the index o refraction of the disks is n=1.5, what fraction of the light is transmitted? Neglect absorption, internal multiple reflections, and interference effects.


Homework Equations


T = 1+R
R = (n1-n2)/(n1+n2), where n is the index of refraction depending on the material

Itotal is proportional to |Etotal|^2 = Etot * (Etot*) where (Etot*) is the complex conjugate.



The Attempt at a Solution


R = (1-1.5)/(1+1.5) = -0.20: going from air to the disk1
Similar calculations for air to disk1, disk1 to air, air to disk2, and disk2 to air.

I tried to calculate Etotal as:
Etotal = -0.20*E0 + 0.20E0* e^(i*delta)
delta = 2kd = 2*(2pi/lambda)*d where d = thickness of the disc
but I am not given a thickness...

Am I missing an equation I need to use? Approaching this from the wrong angle?
Any advice would help! Thank you.
 
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You've got an error in your equation for reflectivity. It should be ((n1 - n2)/(n1 +n2))^2

which gives me an r = 0.04 or 4%. So that means 96% of light incident on each plate will transmit through... work from there:)

Also for this thickness won't matter too much but remember that there is an interface at the front and the back of the plate... so really you've got 4 interfaces to find the transmission through.
 
Thanks lambduh! I think I figured it out. :)
 
is not it R+T=1 giving T=1-R?
 
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