Solve Limit Problem: SQRT(-2)/(4-x) as x Approaches 4

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The limit problem involves evaluating lim x->4- -(2)/(sqrt(4-x). As x approaches 4 from the left, the expression in the denominator, sqrt(4-x), approaches zero, causing the overall fraction to trend towards negative infinity. The numerator remains constant at -2, reinforcing that the limit diverges to -∞. Thus, the limit exists and is equal to -∞. This conclusion is reached by analyzing the behavior of the function as x nears 4 from the negative side.
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Homework Statement

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Determine if the limit exists as a number, ∞, -∞ or DNE
lim x->4- -(2)/(sqrt(4-x))

The Attempt at a Solution


lim x->4-...

I honestly don't know how to solve. Because I don't know what to do with the sqrt function. If someone could lead me in the right direction here that would be great.
Thank you
 
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Niaboc67 said:

Homework Statement


Determine if the limit exists as a number, ∞, -∞ or DNE
lim x->4- -(2)/(sqrt(4-x))

The Attempt at a Solution


lim x->4-...

I honestly don't know how to solve. Because I don't know what to do with the sqrt function. If someone could lead me in the right direction here that would be great.
Thank you
This is actually pretty straightforward. The numerator doesn't change. What happens to the denominator as x gets closer to 4 from the left?
 
Looks like it's getting smaller and smaller from this graph I am looking at for 1/sqrt(x)?
 
Niaboc67 said:
Looks like it's getting smaller and smaller from this graph I am looking at for 1/sqrt(x)?
Can you be more specific? x is approaching 4 from the left.
What is the overall fraction doing?
 
I solved it. It was lim as x approaches 4 from the negative side. so I put it must be something like -2/sqrt(4-3.9999) so inf digits and therefore, -inf
 
Niaboc67 said:
I solved it. It was lim as x approaches 4 from the negative side. so I put it must be something like -2/sqrt(4-3.9999) so inf digits and therefore, -inf

Yes and that is exactly how you want to think about it.
 
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