Solve Motion Problem: 50m Dropped Camera in 2.0m/s Descent

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A hot air balloon descends at 2.0 m/s when a camera is dropped from 50 m above the ground. The initial poster attempted to calculate the time to reach the ground using a kinematic equation but arrived at an incorrect answer of 2.9 seconds. Other participants suggest using a simpler kinematic formula that relates initial velocity, distance, and acceleration due to gravity to find the correct time. The discussion emphasizes the importance of selecting the right equations for solving motion problems. The thread highlights the collaborative nature of problem-solving in physics.
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can someone help me with this problem? A hot air balloon is descending at a rate of 2.0 m/s when a passenger drops a camera. (a) If the camera is 50 m above the ground when it is dropped, how long does it take to reach the ground? (b) What is its velocity just before it lands? Let upward be the positive direction for this problem.

i did part a by this formula. 50 = (-2.0m/s)t + (1/2)(-10m/s2)t2
s2 = s squared t2 = t squared
i tried to solve for t and i got 2.9, but that not the right answer. anyone know what i did wrong?
 
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oh sorry i just saw the sticky for the homework forum. i'll post it there
 
Rather than forcing yourself to solve a quadratic equation, try using another simpler kinematic formula. You know initial velocity, distance, and acceleration due to gravity, and you need to know time: what formula relates all those variables?
 
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