Solve Normal Distribution Homework with Mean 5, Standard Deviation 4

sisyphus0321
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Homework Statement


Assume x is normally distributed with a mean of 5 and standard deviation of 4. Determine value of x that solves:
P(-X<x-5<X) = .99


Homework Equations


I have been using normalCDF and inverse functions on the TI-84 to solve, and I understand how to do these without the calc as well using the standard (x-mean)/stand dev techniques.


The Attempt at a Solution


I have a good understanding of how to work the general problems as this is the last one out of 50 I have solved. The issue is how to start this one? The teacher left a mysterious hint: Distribution?
 
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sisyphus0321 said:

Homework Statement


Assume x is normally distributed with a mean of 5 and standard deviation of 4. Determine value of x that solves:
P(-X<x-5<X) = .99
From the probability above, what you want to solve for is X, not x.
sisyphus0321 said:

Homework Equations


I have been using normalCDF and inverse functions on the TI-84 to solve, and I understand how to do these without the calc as well using the standard (x-mean)/stand dev techniques.


The Attempt at a Solution


I have a good understanding of how to work the general problems as this is the last one out of 50 I have solved. The issue is how to start this one? The teacher left a mysterious hint: Distribution?

You know that your random variable X is n(5, 4). If you let Y = X - 5, how is Y distributed? What would you need to do to get a probability involving Z, the standard normal n(0, 1) random variable? How should your original probability be rewritten so that it involves Z (and from which you can get the values you need from a table or maybe your TI?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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