Solve Plane Intersecting Lines & Parallel to X-Axis

kaybaby
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Homework Statement


Find the equation of the plane that passes through the line of intersection of the planes 4x - 3y - z - 1 = 0 and 2x + 4y + z - 5 = 0 and parallel to the x - axis.



Homework Equations





The Attempt at a Solution


The equation of the plane: 4x+2kx-3y+k4y-z+kz-1-k5=0

do i then assume the plane parallel to the x-axis has points (1,0,0)?

then sub into the equation and solved k=-2

therefore the equation will be =-11y+3z-9?
 
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kaybaby said:

Homework Statement


Find the equation of the plane that passes through the line of intersection of the planes 4x - 3y - z - 1 = 0 and 2x + 4y + z - 5 = 0 and parallel to the x - axis.



Homework Equations





The Attempt at a Solution


The equation of the plane: 4x+2kx-3y+k4y-z+kz-1-k5=0

do i then assume the plane parallel to the x-axis has points (1,0,0)?

then sub into the equation and solved k=-2

therefore the equation will be =-11y+3z-9?

Assuming your first general equation of the planes is correct, then this method is correct. However one minor point: It sounds as though you never really showed that 0=-11y+3z-9 is parallel to the x-axis, but this is pretty trivial (you showed that if a plane of the desired form exists and that is parallel to the x-axis, then it must be this, but what if no plane of the desired form exists that is parallel to the x-axis?).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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