Solve Precal Homework Questions with Step-by-Step Solutions | Need Help?"

  • Thread starter Thread starter psp101
  • Start date Start date
  • Tags Tags
    Homework
AI Thread Summary
The discussion revolves around two precalculus homework problems that lack clarity and complete instructions. The first problem involves the function T(t) = 4t/(t^2+1) + 98.6, but the user struggles to find the variable t and questions the validity of their calculations. The second problem presents P(x) = 1500/(x^2-6x+10) without specifying what needs to be done with it, leading to confusion. Participants emphasize the importance of providing complete problem statements to facilitate proper assistance. Overall, the thread highlights the necessity of clear instructions in math problems for effective problem-solving.
psp101
Messages
8
Reaction score
0
precal homework I need help please

Homework Statement





Homework Equations




1.T(t)=4t/(t^2+1)+98.6
find T,t

2.P(x)=1500/(x^2-6x+10)

The Attempt at a Solution



1.4t/t^2+1=98.6
sub t=2
4t/2(2)+1=98.6
T=8/5+98.6
1.6+98.2=100.2
not sure how to find t

I don't know how to even attempt question 2
 
Physics news on Phys.org


I'm not even sure what you are supposed to be doing either. Why don't you supply a complete problem statement?
 


Yes, please provide a complete statement of the problem.
 


psp101 said:

Homework Statement





Homework Equations




1.T(t)=4t/(t^2+1)+98.6
find T,t
For one thing, this makes no sense. There t can be anything with a corresponding value for T.

2.P(x)=1500/(x^2-6x+10)
This is a function. What are you supposed to do with it?

The Attempt at a Solution



1.4t/t^2+1=98.6
This is true if the original equation were 4t/(t^2+1)+98.6= 197.2 or if you meant to write
T(t)= 4t/(t^2+ 1)+ 98.6. But you did not write either of those.

sub t=2
Why?

4t/2(2)+1=98.6
T=8/5+98.6
1.6+98.2=100.2
not sure how to find t
? You just declared that it was "2"! I have no idea what you are even trying to do.

I don't know how to even attempt question 2
That's probably because there is NO "question 2". An equation is not a question. Go back and read the problems again and find out exactly what you are asked to do. Do not just look at the equations, read the instructions. Once again, an equation is not a question nor a problem. You have to be asked a question about the equation or told to do something with it.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top