Solve Quick Force Problem: Calculate Tensions in Ropes, w & θ

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The problem involves two blocks on a frictionless incline, each with weight w, connected by ropes. The tension between the blocks is calculated as Tbetween = w*sin θ. The tension in the rope connected to the wall is determined to be Twall = 2w*sin θ, accounting for the forces from both blocks. The calculations are confirmed as correct by other participants in the discussion. This demonstrates the application of basic physics principles to solve for tensions in a system of connected objects.
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Homework Statement


Two blocks, each with weight w, are held in place on a frictionless incline. Block A is connected to a wall with a rope and block B is connected with another rope to block A. Calculate the tension in both ropes in terms of w and θ. So, the rope connecting each other and also the one against the wall.


Homework Equations





The Attempt at a Solution



For the tension between the blocks I got Tbetween = w*sin θ.

But then for the tension of the rope connected to the wall. It would be have to be double because it's taking on the pull from block B and pull from block A. So the tension from the wall would be Twall = 2w*sin θ. Am I doing this correctly? Thanks.
 
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Yes, you are correct. :smile:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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