Solve R1 in Rt = R3 + [ ( 1/R1 + 1/R2 ) ^-1 ] for Parallel Circuits

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To solve for R1 in the equation Rt = R3 + [ ( 1/R1 + 1/R2 ) ^-1 ], first isolate the inverse term by subtracting R3 from both sides. This leads to Rt - R3 = ( 1/R1 + 1/R2 )^-1. Taking the reciprocal gives 1/(Rt - R3) = 1/R1 + 1/R2. From here, further manipulation allows for R1 to be expressed in terms of Rt, R2, and R3. The discussion focuses on rearranging the formula for clarity in parallel circuit calculations.
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Homework Statement



Rearrange formula for series and parallel circuit combination.
Make R1 the subject of the formula : Rt = R3 + [ ( 1/R1 + 1/R2 ) ^-1 ]

Homework Equations



Rt = R3 + [ ( 1/R1 + 1/R2 ) ^-1 ]

The Attempt at a Solution



I am unsure as to how to get rid of the inverse? please help.
 
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Rt = R3 + ( 1/R1 + 1/R2 )-1

Rt - R3 = ( 1/R1 + 1/R2 )-1

1/(Rt - R3) = 1/R1 + 1/R2

Continue...
 

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