Solve RC Circuit Problem: Find Time of Current > 50mA

AI Thread Summary
The discussion revolves around calculating the time a current exceeds 50 mA in an RC circuit involving a 120 micro-farad capacitor charged to 210 V. The initial current is determined using Ohm's law, resulting in an initial current of 0.117 A when the resistance of the body is 1.8 kilo-ohms. The equation for current over time is established as i(t) = (V/R)e^(-t/(RC)). After solving for the time when the current drops to 50 mA, the correct answer is found to be approximately 0.184 seconds. The participants clarify the role of voltage in the calculations and confirm the solution.
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Homework Statement


Suppose a 120 micro-farad capacitor from a camera flash unit retains voltage of 210 V when an unwary student removes it from the camera. If the student accidentally touches the two terminals with his hands, and if the resistance of his body between his hands is 1.8 kilo-ohms, for how long will the current across his chest exceed the danger level of 50 mA?

Homework Equations


q(t)=Qe^(-t/(RC))
i(t)=(-Q/(RC))e^(-t/(RC))
V=q/C
i=(dq)/(dt)

The Attempt at a Solution


I'm not sure where the voltage comes into this question. I assume I don't just ignore that piece of given information. I wrote out all the equation, just like above, and I'm not sure how to put them together to find the correct time.

Thanks in advance!
 
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What's the initial current?
 
gneill said:
What's the initial current?

No value is given.
 
kcombs said:
No value is given.
So you will have to calculate it from what is given...
 
gneill said:
So you will have to calculate it from what is given...
Okay. I can calculate that, but how does voltage come into the picture?
 
kcombs said:
Okay. I can calculate that, but how does voltage come into the picture?
What is the initial voltage across the load resistance?
 
gneill said:
What is the initial voltage across the load resistance?
Actually, I'm not sure it's correct but this is what I did:
q=VC
i(t)=(V/R)e^(-t/(RC)) which, due to t=0, simplifies to i(t)=V/R
When I plugged in numbers I got .117 A
 
kcombs said:
Actually, I'm not sure it's correct but this is what I did:
q=VC
i(t)=(V/R)e^(-t/(RC)) which, due to t=0, simplifies to i(t)=V/R
When I plugged in numbers I got .117 A
Yes, the initial current is indeed given by V/R , and your equation for i(t), namely,

i(t)=(V/R)e^(-t/(RC))

looks good.

So now you have an equation for i(t); can you solve for the time when i(t) = 50 mA?
 
gneill said:
Yes, the initial current is indeed given by V/R , and your equation for i(t), namely,

i(t)=(V/R)e^(-t/(RC))

looks good.

So now you have an equation for i(t); can you solve for the time when i(t) = 50 mA?

I just got t=.184 s, which is the correct answer. Thanks for you help! I was definitely overthinking that!
 
  • #10
Well done. Glad I could help!
 

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