Solve Rock Problem Part 2: Time to Push 50Kg Rock 10m

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To solve the problem of pushing a 50kg rock 10 meters with an acceleration of 0.16 m/s², the appropriate kinematic equation is d = vi*t + 1/2*a*t². Given that the initial velocity (vi) is 0 m/s, the equation simplifies to 10 = 1/2*(0.16)*t². Rearranging this, we eliminate the initial velocity term, leading to 10 = 0.08*t². Solving for t involves isolating t², resulting in t = √(10/0.08), which can then be calculated to find the time required to push the rock.
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This is the second hardest question on my test, how long does it take to push a rock 10m.

50Kg rock
10 m is the distance
0.16m/s2 is the acceleration

Does anyone know which kinematics equation I should use for this problem.
 
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The four kinematic equations are:

d = vi*t + 1/2*a*t2

vf = vi + a*t

vf2 = vi2 + 2*a*d

d = vi + vf/2 *t

You want to pick the equation that has a "t" in it, and the one that has the most of your information already provided.

P.S. your initial velocity is 0 m/s, remember! :wink:
 
I know its the first equation since i have all the information except for t, but I'm not good at rearranging question so can you help me just a bit more. Really appreciate it.
 
ok, so let's substitute the values for what we "know"

d = vi*t + 1/2*a*t2, which would equal:

10 = (0)*t + 1/2*(.16)*t2

we want to try and solve for t, in the first part of the equation, (0)*t, we know that equals 0, so we can get rid of that part, now our equation is:

10 = 1/2*(.16)*t2

can you take it from there?
 
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