Solve the Daring 510-N Swimmer's Minimum Speed Physics Problem"

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Homework Help Overview

The problem involves a swimmer who dives off a cliff and needs to determine the minimum horizontal speed required to clear a ledge below. The context is within the subject area of projectile motion in physics.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to find time and horizontal distance. There is a suggestion to treat the swimmer as a projectile and to consider the height of the dive. Some participants question the relevance of the swimmer's mass in this context.

Discussion Status

The discussion is ongoing, with participants offering initial guidance on equations and interpretations of the problem. There is no explicit consensus yet, but several lines of reasoning are being explored.

Contextual Notes

Participants are working with the assumption that the swimmer's mass does not affect the outcome in this scenario, and they are focusing on the horizontal and vertical components of motion.

smadina4
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A daring 510-N swimmer dives off a cliff with a running horizontal leap. What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is 1.75 m wide and 9.00 m below the top of the cliff?
 
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You can find the time by using y=y_0+v_0t+.5at^2. That should get you started...
 
Consider her to be a projectile who is launching at 0 degrees to the horizontal and at a height of 9 metres. i don't think, ( and i jus looked at the problem offhandedly) that the mass of the diver comes into play.
now write equations for the vertical height and the horizontal. Msg me or post if u get stuck...after this, its just simple algebra.

RELATED EQUATIONS:

y = u \sin \theta - \frac{1}{2} g t^2

x = u \cos \theta t
 
smooth sid. msg me or post me...
 

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