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Solve the differential equation with constant coefficients
- Thread starter Fatima Hasan
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mjc123
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How do you get √56? Shouldn't it be (√52)/4 = (√13)/2?
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mjc123
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Looks OK to me.
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Mark44
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1. In the future, please post questions about differential equations in the Calculus & Beyond section. I will move the ones you have posted in the Precalc section.Fatima Hasan said:
2. You don't need to ask us to check your work for these kinds of problems. Just substitute your solution in the original diff. equation.
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Hello,
This is the attachment, the steps to solution are pretty clear. I guess there is a mistake on the highlighted part that prompts this thread.
Ought to be ##3^{n+1} (n+2)-6## and not ##3^n(n+2)-6##. Unless i missed something, on another note, i find the first method (induction) better than second one (method of differences).
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