Solve the fallowing by factoring and making appropriate sign charts.

AI Thread Summary
The discussion revolves around solving the inequality 2x^2 + 4x ≤ 3 by factoring and using sign charts. The initial attempt to factor the expression after rearranging it to 2x^2 + 4x - 3 ≤ 0 proves unsuccessful, as none of the proposed factorizations work. Participants express confusion regarding the requirement to solve by factoring, questioning whether using the quadratic formula might be necessary instead. Ultimately, the consensus suggests that if factoring fails, the quadratic formula is a viable alternative for finding the solution. The conversation highlights the challenges of factoring certain quadratic inequalities in calculus.
epkid08
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Homework Statement


Solve the fallowing by factoring and making appropriate sign charts.
2x^2+4x\leq3


Homework Equations


The Attempt at a Solution


It simply does not factor the way I want it to(unless I did something wrong). I don't think it wants me to use the quadratic formula, and completing the square won't get me anywhere. Am I missing something?
 
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Let's try:
Add (-3) to both sides,
2x^2 + 4x - 3 <= 0

Can we factorize the lefthand side?

(2x_____ -1 ) (x_____ +3 )
(2x_____ +1 ) (x_____ -3 )
(2x_____ -3 ) (x_____ +1 )
(2x_____ +3 ) (x_____ -1 )
Do ANY of those four work? If yes, then factored/
If no, then use quadratic formula solution.
 
I guess I'll just use the formula.
 
epkid08 said:
I guess I'll just use the formula.

That is the best choice; I examined the four different arrangements and none of them will multiply to give the trinomial expression. Are you sure that YOUR instructions are to solve by factoring?
 
Oh yes I am, I'm doing this in a review packet for Calc2. The only reason I posted it was because I was confused by the directions:confused:.
 
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